Did you know?

Fnet x =F gx +F fs. Now the net force in the x provides our acceleration, since our acceleration is centripetal not tangential the net force is the centripetal force. F c =F gx +F fs. Then substitute in. mv 2 /r=mgsinθ+µ s F n. mv 2 /r=mgsinθ+µ s F gy. mv 2 /r=mgsinθ+µ s mgcosθ. Solve for μ s.Also, the static friction would never be larger than the weight component - because then there would be a net force up along the incline, and the ball would start rolling upwards. This also doesn't actually happen, so that also can't be true. The true situation must be that the static friction is smaller than the weight component.F_ {g,x}=mg\sin {\theta}=2\times 9.8\times\sin {20}=6.7\text { N} F g,x = mgsinθ = 2× 9.8×sin20 = 6.7 N. This must be equal to the force of static friction holding the book in place. Another value possible to find in this analysis is the coefficient of static friction.

Centripetal acceleration is given by a=v^2/r. The minimum friction coefficient required is 0.4. (friction coefficients have no units) To find a force we need to know something about a mass, and we haven't been told the mass of the car. Let's just call it 'm' and leave it at that for the moment, because I have a feeling it will cancel out in the end. The centripetal force is given by F_"cent ...To find the coefficient of static friction, you can use the formula µ = v^2/rg, where µ is the coefficient of static friction, v is the velocity, r is the radius, and g is the acceleration due to gravity. This formula assumes that the object is moving in a circular path with a constant speed. 2. Can I use any unit for velocity and radius when ...What is the minimum possible value of the coefficient of static friction force between the box and the floor? a. 131 N (the static friction force is fs is less than or equal to μkn. For an object with no acceleration at rest on a surface, fs equals to the particular value required to keep the object at rest on the surface) b. .355 See ...If the coefficient of static friction is 0.45, you would have to exert a force parallel to the floor greater than. f s ... Therefore, we can find the coefficient of kinetic friction by first finding the normal force of the skier on a slope. The normal force is always perpendicular to the surface, and since there is no motion perpendicular to ...To find the minimum coefficient of static friction needed for the car to safely round the curve, the maximum friction force can be found using the equation u = Ff / Fn, where Ff is the maximum friction force and Fn is the normal force. Since the car is not skidding, the maximum friction force is equal to the centripetal force, giving a ...

Physics ExplainedChapter 9: Torque and EquilibriumIn this video: A ladder leans up against a frictionless wall. A person moves part way up the ladder. What ...OpenVPN is an open source virtual private network that can allow your employees to securely connect to your business servers. For your small business, this means that your employee...The federal minimum wage remains a paltry $7.25 an hour. By clicking "TRY IT", I agree to receive newsletters and promotions from Money and its partners. I agree to Money's Terms o... ….

Reader Q&A - also see RECOMMENDED ARTICLES & FAQs. How to find the minimum coefficient of static friction. Possible cause: Not clear how to find the minimum coefficient of static friction.

As deadly fires burn across California, some of the firefighters risking their lives on the front lines are earning minimum wage By clicking "TRY IT", I agree to receive newsletter...To find the minimum coefficient μs of static friction between the road and the car, we need to equate the centripetal force (Fc) to the maximum static friction force (fs). Rearranging the equation, we have μs = Fc / N = fs/mg. Substituting the values given, we can calculate the value of μs.

What minimum coefficient of friction do you need to get a half Atwood machine to start moving?Here are all the other Atwood Machine problems.1. Normal Plain ...This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: (b) What If? What would the minimum value of the coefficient of static friction need to be for the system not to move when released from rest? L.

we energies outage (a) Calculate the acceleration of the seed, assuming that it does not slip. (b) What is the minimum value of the coefficient of static friction between the seed and the turntable if the seed is not to slip? (c) Suppose that the turntable achieves its angular speed by starting from rest and undergoing a constant angular acceleration for 0.29 s.Physics questions and answers. Find the minimum coefficient of static friction between block A and the 30 degree incline necessary to keep both blocks at rest if the coefficient of friction between B and the incline is zero and the blocks have equal mass. Use this minimum as the value of the coefficient between A and the incline for parts (b ... truist bank reading pamecklenburg inmate inquiry A horizontal force F acts on the 7-kg block. (a) Draw a free-body diagram for each block. (h) Calculate the magnitude of the applied force F necessary to maintain an acceleration of 5 m/s^2 . (e) Find the minimum coefficient of static friction necessary to prevent the 3-kg block from slipping.a)What is the minimum coefficient of static friction (μ s) min is need to prevent it from sliding down? b) When the surface μ s is 0.30 {which is less than the (μ s) min , this means the block is going to slide down the incline} , to prevent the block sliding, a horizontal force F is applied to the block. Please find the magnitude of this ... portfolio planners centereach ny The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03. Figure 4.29 (a) Calculate the minimum force F he must exert to get the block moving. N (b) What is its acceleration once it starts to move, if that force is maintained? ... where μ k is kinetic coefficient of friction. This force equals mass*a, where a ...Physics questions and answers. r ġ A carnival ride with a radius of 10 m rotates at a rate of 2.0 radians per second. Calculate the minimum coefficient of static friction between the walls of the ride and the riders stationary relative to the wall without the presence of the floor of the ride. Use 10 N/kg for g. green door beauty spakinney drugs essex8449 west bellfort The symbol ≤ ≤ size 12{ <= {}} {} means less than or equal to, implying that static friction can have a minimum and a maximum value of μ s N μ s N size 12{μ rSub { size 8{s} } N} {}. Static friction is a responsive force that increases to be equal and opposite to whatever force is exerted, up to its maximum limit. task manager r34 The federal minimum wage remains a paltry $7.25 an hour. By clicking "TRY IT", I agree to receive newsletters and promotions from Money and its partners. I agree to Money's Terms o... fortnite gif wallpaperssimple tweaks ff14my doculivery com dollar tree sign in Most stock market investors want to maximize their potential for profit, while minimizing their exposure to financial risk. Beta is a statistical measure that allows investors to a...